Tuple to Nested Object

约 136 字小于 1 分钟

2026-02-11

题目

Given a tuple type T that only contains string type, and a type U, build an object recursively.

type a = TupleToNestedObject<['a'], string> // {a: string}
type b = TupleToNestedObject<['a', 'b'], number> // {a: {b: number}}
type c = TupleToNestedObject<[], boolean> // boolean. if the tuple is empty, just return the U type

解题思路

待补充

答案

type TupleToNestedObject<T, U> = any

验证

import type { Equal, Expect } from '@type-challenges/utils'

type cases = [
  Expect<Equal<TupleToNestedObject<['a'], string>, { a: string }>>,
  Expect<Equal<TupleToNestedObject<['a', 'b'], number>, { a: { b: number } }>>,
  Expect<Equal<TupleToNestedObject<['a', 'b', 'c'], boolean>, { a: { b: { c: boolean } } }>>,
  Expect<Equal<TupleToNestedObject<[], boolean>, boolean>>,
]

参考

无