Permutation
题目
实现联合类型的全排列，将联合类型转换成所有可能的全排列数组的联合类型。
type perm = Permutation<'A' | 'B' | 'C'> // ['A', 'B', 'C'] | ['A', 'C', 'B'] | ['B', 'A', 'C'] | ['B', 'C', 'A'] | ['C', 'A', 'B'] | ['C', 'B', 'A']解题思路
待补充
答案
type Permutation<T> = any验证
import type { Equal, Expect } from '@type-challenges/utils'
type cases = [
Expect<Equal<Permutation<'A'>, ['A']>>,
Expect<Equal<Permutation<'A' | 'B' | 'C'>, ['A', 'B', 'C'] | ['A', 'C', 'B'] | ['B', 'A', 'C'] | ['B', 'C', 'A'] | ['C', 'A', 'B'] | ['C', 'B', 'A']>>,
Expect<Equal<Permutation<'B' | 'A' | 'C'>, ['A', 'B', 'C'] | ['A', 'C', 'B'] | ['B', 'A', 'C'] | ['B', 'C', 'A'] | ['C', 'A', 'B'] | ['C', 'B', 'A']>>,
Expect<Equal<Permutation<boolean>, [false, true] | [true, false]>>,
Expect<Equal<Permutation<never>, []>>,
]参考
无
