Parse URL Params
约 119 字小于 1 分钟
2026-02-11
题目
You're required to implement a type-level parser to parse URL params string into an Union.
ParseUrlParams<':id'> // id
ParseUrlParams<'posts/:id'> // id
ParseUrlParams<'posts/:id/:user'> // id | user解题思路
待补充
答案
type ParseUrlParams<T> = any验证
import type { Equal, Expect } from '@type-challenges/utils'
type cases = [
Expect<Equal<ParseUrlParams<''>, never>>,
Expect<Equal<ParseUrlParams<':id'>, 'id'>>,
Expect<Equal<ParseUrlParams<'posts/:id'>, 'id'>>,
Expect<Equal<ParseUrlParams<'posts/:id/'>, 'id'>>,
Expect<Equal<ParseUrlParams<'posts/:id/:user'>, 'id' | 'user'>>,
Expect<Equal<ParseUrlParams<'posts/:id/:user/like'>, 'id' | 'user'>>,
]参考
无
