L0v3ch4n

外观

Parse URL Params

约 119 字小于 1 分钟

2026-02-11

题目

You're required to implement a type-level parser to parse URL params string into an Union.

ParseUrlParams<':id'> // id
ParseUrlParams<'posts/:id'> // id
ParseUrlParams<'posts/:id/:user'> // id | user

解题思路

待补充

答案

type ParseUrlParams<T> = any

验证

import type { Equal, Expect } from '@type-challenges/utils'

type cases = [
  Expect<Equal<ParseUrlParams<''>, never>>,
  Expect<Equal<ParseUrlParams<':id'>, 'id'>>,
  Expect<Equal<ParseUrlParams<'posts/:id'>, 'id'>>,
  Expect<Equal<ParseUrlParams<'posts/:id/'>, 'id'>>,
  Expect<Equal<ParseUrlParams<'posts/:id/:user'>, 'id' | 'user'>>,
  Expect<Equal<ParseUrlParams<'posts/:id/:user/like'>, 'id' | 'user'>>,
]

参考

无