ExtractToObject

约 215 字小于 1 分钟

2026-02-11

题目

Implement a type that extract prop value to the interface. The type takes the two arguments. The output should be an object with the prop values. Prop value is object.

For example

interface Test { id: '1', myProp: { foo: '2' } }
type Result = ExtractToObject<Test, 'myProp'> // expected to be { id: '1', foo: '2' }

解题思路

待补充

答案

type ExtractToObject<T, U> = any

验证

import type { Equal, Expect } from '@type-challenges/utils'

interface test1 { id: '1', myProp: { foo: '2' } }

interface testExpect1 {
  id: '1'
  foo: '2'
}

interface test2 {
  id: '1'
  prop1: { zoo: '2' }
  prop2: { foo: '4' }
}

interface testExpect2 {
  id: '1'
  prop1: { zoo: '2' }
  foo: '4'
}

interface test3 {
  prop1: { zoo: '2', a: 2, b: 4, c: 7 }
  prop2: { foo: '4', v: 2, d: 4, g: 7 }
  k: 289
}

interface testExpect3 {
  zoo: '2'
  a: 2
  b: 4
  c: 7
  prop2: { foo: '4', v: 2, d: 4, g: 7 }
  k: 289
}

interface test4 { id: '1', myProp: { foo: '2' } }

interface testExpect4 {
  id: '1'
  myProp: { foo: '2' }
}

type cases = [
  Expect<Equal<ExtractToObject<test1, 'myProp'>, testExpect1>>,
  Expect<Equal<ExtractToObject<test2, 'prop2'>, testExpect2>>,
  Expect<Equal<ExtractToObject<test3, 'prop1'>, testExpect3>>,
  // @ts-expect-error
  Expect<Equal<ExtractToObject<test4, 'prop4'>, testExpect4>>,
]

参考

无

贡献者

Cuber-Wei